5x^2-4x-1500=0

Solution for 5x^2-4x-1500=0 equation:

5x^2-4x-1500=0

a = 5; b = -4; c = -1500;
Δ = b2-4ac
Δ = -42-4·5·(-1500)
Δ = 30016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{30016}=\sqrt{64*469}=\sqrt{64}*\sqrt{469}=8\sqrt{469}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-8\sqrt{469}}{2*5}=\frac{4-8\sqrt{469}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+8\sqrt{469}}{2*5}=\frac{4+8\sqrt{469}}{10}
$